f(x) = x² -6x -16 has an absolute minimum on [-5, 5] of A) -25 B) 7 C) 3 D) 11 E) -31

Question

Quizplus · Accepted Answer

The function f(x) = x^2 - 6x - 16 is a quadratic function that opens upwards (since the coefficient of x^2 is positive). The vertex of this parabola, which gives the minimum value, is at x = 3. Substituting x = 3 into the function gives f(3) = 3^2 - 6*3 - 16 = -25. Since 3 is within the interval [-5, 5], the absolute minimum is -25.

F(x) = X2 -6x -16 Has an Absolute Minimum on [-5

F(x) = X² -6x -16 Has an Absolute Minimum on [-5