Let s(t) = t³ - t be a position function of a particle. At 4 the particle's acceleration is A) negative B) positive C) zero

Question

Quizplus · Accepted Answer

The acceleration of the particle is given by the second derivative of the position function, s(t). Taking the second derivative and plugging in t = 4, we get:
s''(4) = 2S1U1P13S1S1F1 - 2F1F1F1S1
Since S1, U1, P13 and F1 are all constants, we can see that the acceleration depends on the signs of S1 and F1: if S1 is positive and F1 is negative, the acceleration will be positive; if S1 is negative and F1 is positive, the acceleration will be negative. Therefore, without more information about the signs of S1 and F1, the best choice is (B) positive, since it is one of the possible outcomes.

Let S(t) = T3 - T Be a Position Function

Let S(t) = T³ - T Be a Position Function