y = cot (sin x). Find dy/dx. A) cos x csc² (sin x) B) - cos x csc² (sin x) C) - sin x csc² (cos x) D) sin x csc² (cos x) E) - sin x csc² (sin x)

Question

Quizplus · Accepted Answer

To find dy/dx for y = cot(sin x), we use the chain rule. First, the derivative of cot(u) with respect to u is -csc^2(u), and then we multiply by the derivative of the inner function sin(x), which is cos(x). Thus, dy/dx = -csc^2(sin x) * cos(x), matching choice B.

Y = Cot (Sin X). Find Dy/dx