The work done by the force F(x, y) = 6x² i + 12y² j acting on a particle that moves along the circle x = cos t, y = sin t, from (1, 0) to (0, 1).

Name: The work done by the force F(x, y) = 6x 2 i + 12y 2 j acting on a particle that moves along the circle x = cos t, y = sin t, from (1, 0) to (0, 1).
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The Answer of The work done by the force F(x, y) = 6x² i + 12y² j acting on a particle that moves along the circle x = cos t, y = sin t, from (1, 0) to (0, 1).

The Work Done by the Force F(x, Y) = 6x2

The Work Done by the Force F(x, Y) = 6x²