The equation of the tangent plane to x = u, y = v, z = u + v² where u = 2 and v = 2 is A) x - 2 + 2(y - 2) + z - 6 = 0 B) x - 2 + 4(y - 2) - z + 6 = 0 C) x - 2 + 2y - 2 + z + 6 = 0 D) x - 2 + 2y - 4 - z + 6 = 0 E) x + 2 + 2y - 4 - z + 6 = 0

Question

Quizplus · Accepted Answer

The tangent plane is found using the partial derivatives of z with respect to u and v. At u=2, v=2, the partial derivatives are 1 and 4, respectively. The equation is x - 2 + 4(y - 2) - z + 6 = 0.

The Equation of the Tangent Plane to X = U