If and $\varepsilon$ = 0.0368, find a smallest positive number $\delta$ such that |f(x) - 16|

Name: If and $\varepsilon$ = 0.0368, find a smallest positive number $\delta$ such that |f(x) - 16| < 0.0368 if 0 < |x - 4| < $\delta$ . A) 0.0072 B) 0.0082 C) 0.0092 D) 0.092 E) 0.0368
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Question

If  and $\varepsilon$ = 0.0368, find a smallest positive number $\delta$  such that |f(x) - 16| < 0.0368 if 0 < |x - 4| < $\delta$ .
A) 0.0072 
B) 0.0082 
C) 0.0092 
D) 0.092 
E) 0.0368

Quizplus · Accepted Answer

The Answer of If  and $\varepsilon$ = 0.0368, find a smallest positive number $\delta$  such that |f(x) - 16| < 0.0368 if 0 < |x - 4| < $\delta$ .
A) 0.0072 
B) 0.0082 
C) 0.0092 
D) 0.092 
E) 0.0368

If And ε\varepsilonε = 00368, Find a Smallest Positive Number δ\deltaδ

If And $\varepsilon$ = 00368, Find a Smallest Positive Number $\delta$