The frequency of electromagnetic radiation required to promote an electron from n = 2 to n = 4 in a Bohr hydrogen atom is Hz. A) 6.2 × 10¹⁴ B) 4.1 × 10^-¹⁹ C) 8.2 × 10¹⁴ D) 4.1 × 10¹⁹ E) 5.4 × 10^-¹⁹

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Quizplus · Accepted Answer

The energy of an electron in a Bohr hydrogen atom is given by E = -13.6/n^2 eV. The energy difference between n = 2 and n = 4 is E = -13.6/4^2 - (-13.6/2^2) = 10.2 eV. The frequency of electromagnetic radiation required to promote an electron from n = 2 to n = 4 is given by f = E/h, where h is Planck's constant. Substituting the values of E and h, we get f = 10.2 eV / (4.14 × 10^-15 eV s) = 2.46 × 10^14 Hz.

The Frequency of Electromagnetic Radiation Required to Promote an Electron