The n = 2 to n = 6 transition in the Bohr hydrogen atom corresponds to the of a photon with a wavelength of _ nm.
A) emission, 411
B) absorption, 657
C) absorption, 411
D) emission, 93.8
E) emission, 389

Question

Quizplus · Accepted Answer

The energy of the photon emitted or absorbed during a transition can be calculated using the formula E = hc/λ, where h is Planck's constant, c is the speed of light, and λ is the wavelength of the photon. For the n = 2 to n = 6 transition in the Bohr hydrogen atom, the photon is absorbed, so we use the absorption formula, and plug in the given values for n:

E = -(13.6 eV) [(1/6^2) - (1/2^2)]
E = 10.2 eV

Then we use this energy to solve for the wavelength:

E = hc/λ
(10.2 eV)(1.602 x 10^-19 J/eV) = (6.626 x 10^-34 J s)(2.998 x 10^8 m/s)/λ
λ = 4.11 x 10^-7 m = 411 nm

Therefore, the correct answer is C: absorption, 411.

The N = 2 to N = 6 Transition in the Bohr