When the electron in a hydrogen atom moves from n = 6 to n = 1, light with a wavelength of
Nm is emitted.
A) 93.8
B) 657
C) 487
D) 411
E) 434

Question

Quizplus · Accepted Answer

The energy of a photon is given by E = hc/λ, where h is Planck's constant, c is the speed of light, and λ is the wavelength. The energy difference between two energy levels in an atom is given by ΔE = E2 - E1, where E2 is the energy of the higher energy level and E1 is the energy of the lower energy level. When an electron moves from a higher energy level to a lower energy level, a photon is emitted with a wavelength that corresponds to the energy difference between the two levels. In this case, the electron moves from n = 6 to n = 1, so the energy difference is ΔE = -2.46 eV. The wavelength of the emitted photon is then given by λ = hc/ΔE = 93.8 nm.

When the Electron in a Hydrogen Atom Moves from N