What is the concentration (M) of CH₃OH in a solution prepared by dissolving 11.7 g of CH₃OH in sufficient water to give exactly 230 mL of solution? A) 11.9 B) 11.9 × 10^-³ C) 1.59 D) 0.0841 E) 1.59 × 10^-³

Question

Quizplus · Accepted Answer

First, we need to convert the mass of CH₃OH to moles using its molar mass: 11.7 g CH₃OH × (1 mol CH₃OH / 116.2 g CH₃OH) = 0.1005 mol CH₃OH Next, we need to calculate the molarity of the solution using the volume given in milliliters: Molarity (M) = moles of solute / liters of solution M = 0.1005 mol / 0.23 L (convert mL to L) M = 0.437 M Finally, we need to round to the correct number of significant figures, which is three since 11.7 g has three significant figures. Therefore, the answer is 1.59 M.

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