A 25.5 mL aliquot of HCl (aq) of unknown concentration was titrated with 0.113 M NaOH (aq). It took 51.2 mL of the base to reach the endpoint of the titration. The concentration (M) of the acid was .
A) 1.02
B) 0.113
C) 0.454
D) 0.114
E) 0.227

Question

Quizplus · Accepted Answer

The concentration of the acid can be calculated using the formula M1V1 = M2V2. Here, M1 is the concentration of HCl, V1 is the volume of HCl, M2 is the concentration of NaOH, and V2 is the volume of NaOH. Solving for M1 gives M1 = (M2 * V2) / V1 = (0.113 M * 51.2 mL) / 25.5 mL = 0.227 M.

A 255 ML Aliquot of HCl (Aq) of Unknown Concentration Was