How many grams of H₃PO₄are in 175 mL of a 3.5 M solution of H₃PO₄?

Question

Quizplus · Accepted Answer

First, we need to calculate the number of moles of H₃PO₄ in the solution using the formula: moles = molarity x volume (in liters) Volume can be converted from milliliters to liters by dividing by 1000: 175 mL = 175/1000 L = 0.175 L moles = 3.5 M x 0.175 L = 0.6125 moles Next, we need to convert the moles of H₃PO₄ to grams using its molar mass. The molar mass of H₃PO₄ can be calculated by adding the molar masses of its individual atoms: (1 x hydrogen atomic mass) + (1 x sulfur atomic mass) + (13 x carbon atomic mass) + (1 x oxygen atomic mass) + (14 x nitrogen atomic mass) = 1.0079 g/mol + 32.06 g/mol + (13 x 12.01 g/mol) + 15.999 g/mol + (14 x 14.01 g/mol) = 337.47 g/mol Finally, we can use the formula: grams = moles x molar mass grams = 0.6125 moles x 337.47 g/mol grams = 206.82 g Therefore, there are 206.82 grams of H₃PO₄ in 175 mL of a 3.5 M solution. To find how many grams are in 1 mL of the solution, we can divide by 175: 206.82 g / 175 mL = 1.18218 g/mL To find how many grams are in 1 mL of the solution, we can multiply 1.18218 g/mL by 1 mL: 1.18218 g/mL x 1 mL = 1.18218 g So there are 1.18218 grams of H₃PO₄ in 1 mL of the solution. To find how many grams are in 175 mL of the solution, we can multiply by 175: 1.18218 g x 175 = 206.3175 g Rounding to two significant figures, we get 206.32 g, which is closest to answer choice A) 60.

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How Many Grams of H₃PO₄are in 175 ML of a 3.5