An aqueous ethanol solution (400 mL) was diluted to 4.00 L, giving a concentration of 0.0400 M. The concentration of the original solution was M.
A) 0.400
B) 2.00
C) 0.200
D) 4.00
E) 1.60

Question

Quizplus · Accepted Answer

The dilution equation $ C_1V_1 = C_2V_2 $ can be used. The final concentration $ C_2 $ is 0.0400 M, and the final volume $ V_2 $ is 4.00 L. The initial volume $ V_1 $ is 0.400 L. Solving for $ C_1 $, we get $ C_1 = \frac{C_2V_2}{V_1} = \frac{0.0400 \times 4.00}{0.400} = 0.400 $ M.

An Aqueous Ethanol Solution (400 ML) Was Diluted to 4