How many grams of CuS are obtained by passing a current of 12 A through a solution of CuSO₄ for 15 minutes ?

Question

Quizplus · Accepted Answer

The steps to solve the problem are:

1. Calculate the total charge passed through the solution:

Current (I) = 12 A
Time (t) = 15 min = 900 s

Total charge(Q) = I * t = 12 A * 900 s = 10800 C

2. Calculate the amount of CuS deposited using Faraday's law:

1 mole of CuS corresponds to 2 moles of electrons (2F), where F is the Faraday constant = 96500 C/mol

2F = 2 * 96500 C/mol = 193000 C/mol

Mass of CuS deposited = (Total charge / 193000) * molar mass of CuS

Molar mass of CuS = 63.5 g/mol + 32.1 g/mol = 95.6 g/mol

Mass of CuS deposited = (10800 C / 193000 C/mol) * 95.6 g/mol = 5.34 g

Therefore, the closest answer is D) 3.6 g.

How Many Grams of CuS Are Obtained by Passing a Current