How many milliliters of 0.120 M NaOH are required to titrate 50.0 mL of 0.0998 M butanoic acid to the equivalence point? The K_aof butanoic acid is 1.5 × 10^-⁵.

Question

Quizplus · Accepted Answer

To find the volume of NaOH required, use the formula M1V1 = M2V2, where M1 and V1 are the molarity and volume of butanoic acid, and M2 and V2 are the molarity and volume of NaOH. Solving for V2 gives (0.0998 M)(50.0 mL) = (0.120 M)(V2), resulting in V2 = 41.6 mL.

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