Calculate the pOH of a 0.0827 M aqueous sodium cyanide solution at 25.0 °C. K_bfor CN^-is 4.9 × 10^-¹⁰.

Name: Calculate the pOH of a 0.0827 M aqueous sodium cyanide solution at 25.0 °C. K b for CN - is 4.9 × 10 - 10 .
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Quizplus · Accepted Answer

The pOH is calculated using the formula pOH = -log[OH⁻]. First, calculate [OH⁻] using the formula [OH⁻] = √(Kb × [CN⁻]), where [CN⁻] = 0.0827 M. Then, pOH = -log(√(4.9 × 10⁻¹⁰ × 0.0827)) ≈ 5.2.

Calculate the POH of a 0