A particular first- order reaction has a rate constant of 1.35 × 10²s^-¹at 25°C. What is the magnitude of k at 75°C if E_a= 85.6 kJ/mol?

Question

Quizplus · Accepted Answer

The Arrhenius equation is:k = Ae^(-Ea/RT)where:k is the rate constantA is the pre-exponential factorEa is the activation energyR is the gas constant (8.314 J/mol·K)T is the temperature in KelvinWe can use this equation to find the rate constant at 75°C. First, we need to convert the temperature to Kelvin:75°C + 273.15 = 348.15 KNow we can plug in the values we know:k = Ae^(-Ea/RT)k = (1.35 × 10^2 s^-1)e^(-85.6 kJ/mol / (8.314 J/mol·K * 348.15 K))k = 1.93 × 10^4 s^-1Therefore, the magnitude of k at 75°C is 1.93 × 10^4 s^-1.

A Particular First- Order Reaction Has a Rate Constant of 1.35