The rate of disappearance of HBr in the gas phase reaction 2HBr (g) → H₂(g) + Br₂(g)
Is 0.190 M s^-¹at 150°C. The rate of reaction is M s^-¹.

Name: The rate of disappearance of HBr in the gas phase reaction 2HBr (g) → H 2 (g) + Br 2 (g) Is 0.190 M s - 1 at 150°C. The rate of reaction is M s - 1 .
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Question

The rate of disappearance of HBr in the gas phase reaction 2HBr (g) → H₂(g) + Br₂(g) Is 0.190 M s^-¹at 150°C. The rate of reaction is M s^-¹.

Quizplus · Accepted Answer

The rate of reaction is half the rate of disappearance of HBr because the stoichiometry of HBr is 2 in the balanced equation. Therefore, the rate of reaction is 0.190 M s⁻¹ / 2 = 0.095 M s⁻¹.

The Rate of Disappearance of HBr in the Gas Phase