A second- order reaction has a half- life of 18 s when the initial concentration of reactant is 0.71 M. The rate constant for this reaction is M^-¹s^-¹.

Question

Quizplus · Accepted Answer

Given data:

Half-life of the reaction, t1/2 = 18 s

Initial concentration of reactant, [A]0 = 0.71 M

We know that for a second-order reaction,

t1/2 = 1 / k[A]0

where k is the rate constant.

Substituting the given values, we get:

18 = 1 / k x 0.71

Solving for k, we get:

k = 7.8 × 10^-2 M^-1s^-1

Therefore, the answer is option B.

A Second- Order Reaction Has a Half- Life of 18