A sample of He gas (2.35 mol) occupies 57.9 L at 300.0 K and 1.00 atm. The volume of this sample is L at 423 K and 1.00 atm.

Name: A sample of He gas (2.35 mol) occupies 57.9 L at 300.0 K and 1.00 atm. The volume of this sample is L at 423 K and 1.00 atm.
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Question

Quizplus · Accepted Answer

According to Charles's Law, V1/T1 = V2/T2. Given V1 = 57.9 L, T1 = 300 K, T2 = 423 K, and P1 = P2 = 1 atm, V2 = V1 * (T2/T1) = 57.9 * (423/300) = 81.6 L.

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