The density of ammonia gas in a 4.32 L container at 837 torr and 45.0 °C is g/L. A) 3.86 B) 0.194 C) 0.717 D) 4.22 × 10^-² E) 0.432

Question

Quizplus · Accepted Answer

First, we need to use the ideal gas law to calculate the number of moles of ammonia gas in the container:
PV = nRT
n = PV/RT
n = (837 torr)(4.32 L)/(0.0821 L·atm/mol·K)(45.0 + 273.15 K)
n = 0.183 mol

Next, we need to use the formula for density, which is mass divided by volume:
density = m/V

To find the mass, we can use the molar mass of ammonia (17.03 g/mol) and the number of moles we calculated earlier:
mass = n × molar mass
mass = 0.183 mol × 17.03 g/mol
mass = 3.11 g

Finally, we can plug the mass and volume into the density formula:
density = 3.11 g/4.32 L
density = 0.717 g/L

Therefore, the best choice is C.

The Density of Ammonia Gas in a 4