A sample of a gas originally at 25 °C and 1.00 atm pressure in a 2.5 L container is allowed to expand until the pressure is 0.85 atm and the temperature is 15 °C. The final volume of the gas is L)
A) 0.38
B) 3.0
C) 2.1
D) 2.6
E) 2.8

Question

Quizplus · Accepted Answer

Using the combined gas law: (P1 * V1) / T1 = (P2 * V2) / T2, where temperatures are in Kelvin. Convert temperatures: 25°C = 298 K, 15°C = 288 K. Solve for V2: (1.00 atm * 2.5 L) / 298 K = (0.85 atm * V2) / 288 K. V2 ≈ 2.8 L.

A Sample of a Gas Originally at 25 °C and 1.00