Imagine a population where A = 0.2 and a = 0.8. Assuming random mating, what is the frequency of each genotype among the zygotes of the next generation?
A) AA = 0.2, Aa = 0, and aa = 0.8
B) AA = 0.40, Aa = 0.16, and aa = 0.44
C) AA = 0.04, Aa = 0.32, and aa = 0.64
D) AA = 0.40, Aa = 0.30, and aa = 0.60

Question

Quizplus · Accepted Answer

Using the Hardy-Weinberg principle, the frequency of AA is (0.2)^2 = 0.04, Aa is 2*(0.2)*(0.8) = 0.32, and aa is (0.8)^2 = 0.64.

Imagine a Population Where a = 0