Last year, during an investigation of the time spent reading emails on a daily basis, researchers found that on Monday the average time was 50 minutes. Office workers claim that with the increased spam and junk mail, this time has now increased. To conduct a test, a sample of 25 employees is selected, with the following results: sample mean = 51.05 minutes and sample standard deviation = 14.2 minutes. What is the critical value for α = .05 to test the hypotheses and apply the critical value rule to determine if the null hypothesis can be rejected.

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The Answer of Last year, during an investigation of the time spent reading emails on a daily basis, researchers found that on Monday the average time was 50 minutes. Office workers claim that with the increased spam and junk mail, this time has now increased. To conduct a test, a sample of 25 employees is selected, with the following results: sample mean = 51.05 minutes and sample standard deviation = 14.2 minutes. What is the critical value for α = .05 to test the hypotheses and apply the critical value rule to determine if the null hypothesis can be rejected.

Last Year, During an Investigation of the Time Spent Reading