Health insurers and the federal government are both putting pressure on hospitals to shorten the average length of stay (LOS) of their patients. In 2003, the average LOS for non-heart patients was 4.6 days. A random sample of 20 hospitals in one state had a mean LOS for non-heart patients in 2008 of 3.8 days and a standard deviation of 1.2 days and is normally distributed. Calculate a 95 percent confidence interval for the population mean LOS for non-heart patients in these hospitals in 2008.
A) [3.24, 4.36]
B) [3.67, 3.93]
C) [3.34, 4.26]
D) [3.38, 4.22]
E) [3.27, 4.33]
Correct Answer:
Verified
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