In 2005, 13,000 Internet users were surveyed and asked about their willingness to pay fees for access to websites. Of these, 2,938 were definitely not willing to pay such fees. How large a sample is necessary to estimate the proportion of interest to within 2 percent in a 95 percent confidence interval?
A) 18
B) 307
C) 1680
D) 2000
E) 2965

Question

Quizplus · Accepted Answer

= 2938 / 13,000 = .226 n = p(1 − p)(z/E)² = .226(.774)(1.96/.02)² = (.1749)(98)² = 1679.7 = 1680

In 2005, 13,000 Internet Users Were Surveyed and Asked About