For the following ANOVA table, the critical value of the studentized range distribution using $\alpha$= 0.05 is ______. $$\begin{array} { | c | c | c | c | c | }
\hline \text { Source of Variation } & \text { SS } & \text { df } & \text { MS } & F \
\hline \text { Treatment } & 36.17 & 2 & 18.08 & 5.66 \
\hline \text { Error } & 28.75 & 9 & 3.19 & \
\hline \text { Total } & 64.92 & 11 & & \
\hline
\end{array}$$
A)1.86
B)3.95
C)9.17
D)1.65
E)1.79

Question

For the following ANOVA table, the critical value of the studentized range distribution using $\alpha$= 0.05 is ______. $$\begin{array} { | c | c | c | c | c | } 
\hline \text { Source of Variation } & \text { SS } & \text { df } & \text { MS } & F \
\hline \text { Treatment } & 36.17 & 2 & 18.08 & 5.66 \
\hline \text { Error } & 28.75 & 9 & 3.19 & \
\hline \text { Total } & 64.92 & 11 & & \
\hline
\end{array}$$
A)1.86
B)3.95
C)9.17
D)1.65
E)1.79

Quizplus · Accepted Answer

The critical value of the studentized range distribution for an ANOVA table is determined by the number of treatments (or groups) and the degrees of freedom for the error term, not directly from the table's F value. Given 3 groups (from 2 degrees of freedom for treatment plus 1) and 9 degrees of freedom for error, and using a significance level of 0.05, standard tables or software for the studentized range distribution typically yield a value around 3.95.

For the Following ANOVA Table, the Critical Value of the Studentized