In American Roulette, there are two zeroes and 36 non-zero numbers (18 red and 18 black).If a player bets 1 unit on red, his chance of winning 1 unit is therefore 18/38 and his chance of losing 1 unit (or winning -1)is 20/38.Let x be the player profit per game.The mean (average)value of x is approximately_______________.
A)0.0526
B)-0.0526
C)1
D)-1
E)0

Question

Quizplus · Accepted Answer

The mean value of x, the player's profit per game, is calculated by taking the weighted average of the outcomes. The player wins 1 unit with a probability of 18/38 and loses 1 unit with a probability of 20/38. Thus, the expected value (mean) is (18/38)*1 + (20/38)*(-1) = -2/38 = -1/19, which is approximately -0.0526.

In American Roulette, There Are Two Zeroes and 36 Non-Zero