A market research team compiled the following discrete probability distribution on the number of sodas the average adult drinks each day.In this distribution, x represents the number of sodas which an adult drinks. $$\begin{array} { | c | c | }
\hline x & P ( x ) \
\hline 0 & 0.30 \
\hline 1 & 0.10 \
\hline 2 & 0.50 \
\hline 3 & 0.10 \
\hline
\end{array}$$ The mean (average)value of x is _______________.
A)1.40
B)1.75
C)2.10
D)2.55
E)3.02

Question

A market research team compiled the following discrete probability distribution on the number of sodas the average adult drinks each day.In this distribution, x represents the number of sodas which an adult drinks. $$\begin{array} { | c | c | } 
\hline x & P ( x ) \
\hline 0 & 0.30 \
\hline 1 & 0.10 \
\hline 2 & 0.50 \
\hline 3 & 0.10 \
\hline
\end{array}$$ The mean (average)value of x is _______________.
A)1.40
B)1.75
C)2.10
D)2.55
E)3.02

Quizplus · Accepted Answer

The mean of a discrete probability distribution is calculated by summing the products of each value of x and its corresponding probability, $ \mu = \sum xP(x) $. Thus, $ \mu = (0)(0.30) + (1)(0.10) + (2)(0.50) + (3)(0.10) = 0 + 0.10 + 1.00 + 0.30 = 1.40 $.

A Market Research Team Compiled the Following Discrete Probability Distribution xP(x)00.3010.1020.5030.10\begin{array} { | c | c | } \hline x & P ( x ) \\\hline 0 & 0.30 \\\hline 1 & 0.10 \\\hline 2 & 0.50 \\\hline 3 & 0.10 \\\hline\end{array}x0123​P(x)0.300.100.500.10​​

A Market Research Team Compiled the Following Discrete Probability Distribution $\begin{array} { | c | c | } \hline x & P ( x ) \\\hline 0 & 0.30 \\\hline 1 & 0.10 \\\hline 2 & 0.50 \\\hline 3 & 0.10 \\\hline\end{array}$