Calculate ?_rG° at 25.0 °C for the reaction below. 2 Na(s) + 2 H₂O( $\ell$ ) ? 2 NaOH(aq) + H₂(g) Given: ?_rH° = -366.6 kJ/mol-rxn and ?_rS° = -154.2 J/K?mol-rxn. A) -371.2 kJ/mol-rxn B) -320.6 kJ/mol-rxn C) -215.4 kJ/mol-rxn D) +371.2 kJ/mol-rxn E) +4634.9 kJ/mol-rxn

Question

Quizplus · Accepted Answer

To calculate ΔrG° at 25.0 °C (298 K), use the formula: ΔrG° = ΔrH° - TΔrS°. Convert ΔrS° to kJ by dividing by 1000: -154.2 J/K?mol-rxn = -0.1542 kJ/K?mol-rxn. Then, ΔrG° = -366.6 kJ/mol-rxn - (298 K * -0.1542 kJ/K?mol-rxn) = -366.6 kJ/mol-rxn + 45.994 kJ/mol-rxn = -320.606 kJ/mol-rxn.

Calculate ?rG° at 25 ℓ\ellℓ ) ? 2 NaOH(aq) + H2(g) Given: ?rH° = -366

Calculate ?_rG° at 25 $\ell$ ) ? 2 NaOH(aq) + H₂(g)
Given: ?_rH° = -366