What is Ka at 25°C for the following equilibrium given Kb (CH3NH2) = 4.4 × 10-4 at 25°C.? CH3NH3+(aq) + H2O(l) CH3NH2(aq) + H3O+(aq)
A) 4.4 × 10-4
B) 2.3 × 103
C) 4.4 × 10-10
D) 4.4 × 104
E) 2.3 × 10-11
Correct Answer:
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