An aqueous mixture of phenol and ammonia has initial concentrations of 0.200 M C₆H₅OH(aq) and 0.120 M NH₃(aq). At equilibrium, the C₆H₅O^-(aq) concentration is 0.050 M. Calculate the equilibrium constant, K, for the reaction below. C₆H₅OH(aq) + NH₃(aq) $\rightleftharpoons$ C₆H₅O^- + NH₄⁺(aq)

Question

Quizplus · Accepted Answer

The equilibrium constant K is calculated using the expression K = [C6H5O-][NH4+]/[C6H5OH][NH3]. At equilibrium, [C6H5O-] = 0.050 M, [NH4+] = 0.050 M, [C6H5OH] = 0.200 - 0.050 = 0.150 M, and [NH3] = 0.120 - 0.050 = 0.070 M. Substituting these values gives K = (0.050)(0.050)/(0.150)(0.070) = 0.24.

An Aqueous Mixture of Phenol and Ammonia Has Initial Concentrations ⇌\rightleftharpoons⇌

An Aqueous Mixture of Phenol and Ammonia Has Initial Concentrations $\rightleftharpoons$