When 020 Mole HF Is Dissolved in Water to a Volume

When 0.20 mole HF is dissolved in water to a volume of 1.00 L, 5.8% of the HF dissociates to form F^-(aq) . What is the equilibrium constant for the reaction? HF(aq) + H₂O( $\ell$ ) $\rightleftharpoons$ F^-(aq) + H₃O⁺(aq)

A) 1.3 × 10^-4
B) 7.1 × 10^-4
C) 1.2 × 10^-2
D) 1.7 × 10^-2
E) 6.2 × 10^-2