Nickel crystallizes in a face-centered cubic lattice. The density of the nickel is 8.91 g/cm3. What is the volume of a single unit cell? A) $4.3755313942 \times 10 ^ { - 23 }$ cm³ B) $3.4736512388 \times 10 ^ { - 21 }$ cm³ C) ?? $1.2701419732 \times 10 ^ { - 26 }$ cm³ D) $1.0938828486 \times 10^{ - 23}$ cm³ E) ?? $8.684128097 \times 10 ^ { - 22 }$ cm³

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Quizplus · Accepted Answer

The volume of a single unit cell can be calculated using the formula:V = (a^3 * N)/4where a is the edge length of the unit cell, N is the number of atoms in the unit cell, and 4 is the number of unit cells per atom in a face-centered cubic lattice.The density of nickel is given as 8.91 g/cm3. The molar mass of nickel is 58.69 g/mol. The number of atoms per unit cell can be calculated using the formula:N = (density * N_A * V)/Mwhere N_A is Avogadro's number and M is the molar mass.Substituting the given values into the formula, we get:N = (8.91 g/cm3 * 6.022 * 10^23 atoms/mol * V)/(58.69 g/mol)Solving for V, we get:V = 4.3755313942 * 10^-23 cm3Therefore, the volume of a single unit cell is 4.3755313942 * 10^-23 cm3.

Nickel Crystallizes in a Face-Centered Cubic Lattice 4.3755313942×10−234.3755313942 \times 10 ^ { - 23 }4.3755313942×10−23

Nickel Crystallizes in a Face-Centered Cubic Lattice $4.3755313942 \times 10 ^ { - 23 }$