What quantity, in moles, of hydrogen is consumed when 179.6 kJ of energy is evolved from the combustion of a mixture of H₂(g) and O₂(g) ?
H₂(g) + $\frac { 1 } { 2 }$ O₂(g) ? H₂O(l) ; ?_rH° = -285.8 kJ/mol-rxn

Question

What quantity, in moles, of hydrogen is consumed when 179.6 kJ of energy is evolved from the combustion of a mixture of H₂(g) and O₂(g) ?
H₂(g) +

\frac { 1 } { 2 }

O₂(g) ? H₂O(l) ; ?_rH° = -285.8 kJ/mol-rxn

Quizplus · Accepted Answer

The enthalpy change for the combustion of 1 mol of H2 is -285.8 kJ. Therefore, the number of moles of H2 consumed when 179.6 kJ of energy is evolved is:179.6 kJ / (-285.8 kJ/mol) = 0.6284 mol

What Quantity, in Moles, of Hydrogen Is Consumed When 179 12\frac { 1 } { 2 }21​

What Quantity, in Moles, of Hydrogen Is Consumed When 179 $\frac { 1 } { 2 }$