According to the Reaction Given Below, the Standard Enthalpy Change

According to the reaction given below, the standard enthalpy change for the combustion of 1 mole of propane is -2043.0 kJ.
C₃H₈(g) + 5 O₂(g) ? 3 CO₂(g) + 4 H₂O(g)
Calculate ?_fH° for propane based on the given standard molar enthalpies of formation.
$$\begin{array} { l l } \text { molecule } & \Delta {}_f H ^ { \circ } ( \mathrm { kJ } / \text { mol-rxn } ) \\\hline \mathrm { CO } _ { 2 } ( \mathrm {~g} ) & - 393.5 \\\mathrm { H } _ { 2 } \mathrm { O } ( \mathrm { g } ) & - 241.8\end{array}$$

A) -1407.7 kJ/mol-rxn
B) +104.7 kJ/mol-rxn
C) -104.7 kJ/mol-rxn
D) -4190.7 kJ/mol-rxn
E) +1407.7 kJ/mol-rxn