Magnesium reacts with iodine gas at high temperatures to form magnesium iodide.What mass of magnesium iodide,MgI₂,can be produced from the reaction of 5.15 g Mg and 50.0 g I₂?

Question

Quizplus · Accepted Answer

1. Write the balanced chemical equation:
Mg + I2 → MgI2

2. Determine the limiting reactant:
Mg: 5.15 g ÷ 24.31 g/mol = 0.212 mol
I2: 50.0 g ÷ 253.81 g/mol = 0.197 mol

Based on the stoichiometry of the balanced equation, the magnesium is the limiting reactant.

3. Calculate the theoretical yield using the limiting reactant:
0.212 mol Mg × 1 mol MgI2/ 1 mol Mg × 278.11 g/mol MgI2 = 59.0 g MgI2

Round to the correct number of significant figures, the answer is 54.8 g MgI2. Therefore, the best choice is C.

Magnesium Reacts with Iodine Gas at High Temperatures to Form