Consider the fermentation reaction of glucose: C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
A 1) 00-mol sample of C₆H₁₂O₆ was placed in a vat with 100 g of yeast.If 38.5 g of C₂H₅OH was obtained,what was the percent yield of C₂H₅OH?

Question

Quizplus · Accepted Answer

The theoretical yield of C2H5OH is 92 g (from 1 mol of glucose). The actual yield is 38.5 g, so the percent yield is (38.5/92) * 100 = 41.8%.

Consider the Fermentation Reaction of Glucose: C6H12O6 → 2C2H5OH

Consider the Fermentation Reaction of Glucose: C₆H₁₂O₆ → 2C₂H₅OH