The Distance from Austin, Texas, to Lincoln, Nebraska, Is 822

The distance from Austin, Texas, to Lincoln, Nebraska, is 822 miles by car. Which of the following series of calculations will yield this distance in units of kilometers? (1 in = 2.54 cm (exact) , 1 mi = 5280 ft (exact) , 1 ft = 12 in (exact) )

A) $822 \mathrm { mi } \times \frac { 5280 \mathrm { ft } } { 1 \mathrm { mi } } \times \frac { 1 \mathrm { ft } } { 12 \mathrm { in } } \times \frac { 2.54 \mathrm {~cm} } { 1 \mathrm { in } } \times \frac { 100 \mathrm {~m} } { 1 \mathrm {~cm} } \times \frac { 1 \mathrm {~km} } { 1000 \mathrm {~m} }$
B) $822 \mathrm { mi } \times \frac { 12 \mathrm { ft } } { 1 \mathrm { in } } \times \frac { 1 \mathrm { in } } { 2.54 \mathrm {~cm} } \times \frac { 1760 \mathrm { yd } } { 1 \mathrm { mi } } \times \frac { 1 \mathrm {~km} } { 1000 \mathrm {~m} }$
C) $822 \mathrm { mi } \times \frac { 5280 \mathrm { ft } } { 1 \mathrm { mi } } \times \frac { 12 \mathrm { ft } } { 1 \mathrm { in } } \times \frac { 1 \mathrm {~cm} } { 2.54 \mathrm { in } } \times \frac { 1 \mathrm {~m} } { 100 \mathrm {~cm} } \times \frac { 1 \mathrm {~km} } { 1000 \mathrm {~m} }$
D) $822 \mathrm { mi } \times \frac { 5280 \mathrm { ft } } { 1 \mathrm { mi } } \times \frac { 12 \mathrm { in } } { 1 \mathrm { ft } } \times \frac { 2.54 \mathrm {~cm} } { 1 \mathrm { in } } \times \frac { 1 \mathrm {~m} } { 100 \mathrm {~cm} } \times \frac { 1 \mathrm {~km} } { 1000 \mathrm {~m} }$
E) $822 \mathrm { mi } \times \frac { 12 \mathrm { in } } { 1 \mathrm { ft } } \times \frac { 2.54 \mathrm {~cm} } { 1 \mathrm { ft } } \times \frac { 1 \mathrm {~km} } { 1000 \mathrm {~m} }$