Calculate the molar concentration of a sodium hydroxide solution if 60.00 mL of this solution were required to neutralize 30.00 mL of a 0.150 M hydrochloric acid solution.NaOH(aq)+ HCl(aq)→ NaCl(aq)+ H₂O(l)

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Quizplus · Accepted Answer

The neutralization reaction between NaOH and HCl is a 1:1 molar ratio. To find the molarity of the NaOH solution, we first calculate the moles of HCl using its volume and molarity: $30.00 \, \text{mL} \times 0.150 \, \text{M} = 4.50 \times 10^{-3} \, \text{moles}$. Since the reaction ratio is 1:1, the moles of NaOH required for neutralization are also $4.50 \times 10^{-3}$. The molarity of NaOH is then calculated using its volume: $\frac{4.50 \times 10^{-3} \, \text{moles}}{60.00 \, \text{mL} \times 1 \, \text{L}/1000 \, \text{mL}} = 0.0750 \, \text{M}$.

Calculate the Molar Concentration of a Sodium Hydroxide Solution If