Consider the reversible reaction: N 2 (g)+ 3H 2 (g)? 2NH 3 (g) What is the correct expression for the equilibrium constant,Keq,for this reaction?

The correct expression for the equilibrium constant ($K_{eq}$) is based on the stoichiometry of the reaction, with products in the numerator and reactants in the denominator, each raised to the power of their coefficients in the balanced equation.

Consider the reversible reaction: N 2 (g)+ 3H 2 (g)? 2NH 3 (g) What is the correct expression for the equilibrium constant,Keq,for this reaction?

The correct expression for the equilibrium constant ($K_{eq}$) is based on the stoichiometry of the reaction, with products in the numerator and reactants in the denominator, each raised to the power of their coefficients in the balanced equation.

Solved

Consider the Reversible Reaction: N₂(g)+ 3H₂(g)? 2NH₃(g) What Is the Correct

Question 23

Multiple Choice

Consider the reversible reaction: N₂(g) + 3H₂(g) ? 2NH₃(g) What is the correct expression for the equilibrium constant,Keq,for this reaction?

A) $\frac { \left[ 2 \mathrm { NH } _ { 3 } \right] } { \left[ \mathrm { N } _ { 2 } \right] \left[ 3 \mathrm { H } _ { 2 } \right] }$
B) $\frac { 2 \left[ \mathrm { NH } _ { 3 } \right] } { \left[ \mathrm { N } _ { 2 } \right] 3 \left[ \mathrm { H } _ { 2 } \right] }$
C) $\frac { \left[ \mathrm { NH } _ { 3 } \right] ^ { 2 } } { \left[ \mathrm {~N} _ { 2 } \right] \left[ \mathrm { H } _ { 2 } \right] ^ { 3 } }$
D) $\frac { \left[ \mathrm { N } _ { 2 } \right] \left[ \mathrm { H } _ { 2 } \right] ^ { 3 } } { \left[ \mathrm { NH } _ { 3 } \right] ^ { 2 } }$
E) $\frac { \left[ \mathrm { N } _ { 2 } \right] 3 \left[ \mathrm { H } _ { 2 } \right] } { 2 \left[ \mathrm { NH } _ { 3 } \right] }$