For the reaction 2H₂(g)+ S₂(g)⇌ 2H₂S(g),determine the equilibrium constant at 700oC if at this temperature,the equilibrium concentrations are as follows: [H2] = 0.208 M,[S2] = 1.13 × 10-6M,[H2S] = 0.725 M

Question

Quizplus · Accepted Answer

The equilibrium constant expression for the reaction is Kc = [H2S]^2 / ([H2]^2 * [S2]). Substituting the given concentrations into this expression gives Kc = (0.725^2) / (0.208^2 * 1.13 × 10^-6) = 1.08 × 10^7.

For the Reaction 2H2(g)+ S2(g)⇌ 2H2S(g),determine the Equilibrium Constant at 700oC

For the Reaction 2H₂(g)+ S₂(g)⇌ 2H₂S(g),determine the Equilibrium Constant at 700oC