What is the boiling point of a 1.5 m solution of NaCl? [k_b= 0.52°C/m]

Name: What is the boiling point of a 1.5 m solution of NaCl? [k b = 0.52°C/m]
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The boiling point elevation can be calculated using the formula ΔT_b = i * m * k_b, where i is the van't Hoff factor (2 for NaCl), m is the molality (1.5 m), and k_b is the ebullioscopic constant (0.52°C/m). ΔT_b = 2 * 1.5 * 0.52 = 1.56°C. Adding this to the normal boiling point of water (100°C) gives 101.56°C.

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