Given the following data,calculate the Mann-Whitney statistic U for the stream draining the boreal forest. $\begin{array} { | l | l | l | l | }
\hline \text { Measurements(deciduous) } & \text { Ranks } & \text { Measurements(boreal) } & \text { Ranks } \
\hline 13.1 & 1 & 100.9 & 7 \
\hline 16.9 & 2 & 111.2 & 8 \
\hline 24.2 & 3 & 113.5 & 9 \
\hline 30.6 & 4 & 151.1 & 10 \
\hline 32.8 & 5 & 172.3 & 11 \
\hline 41.1 & 6 & 206.6 & 12 \
\hline 218.8 & 13 & 442.4 & 14 \
\hline n _ { d } = 7 & T _ { d } = 34 & n _ { b } = 7 & T _ { b } = 71 \
\hline
\end{array}$

Question

Given the following data,calculate the Mann-Whitney statistic U for the stream draining the boreal forest. $\begin{array} { | l | l | l | l | } 
\hline \text { Measurements(deciduous) } & \text { Ranks } & \text { Measurements(boreal) } & \text { Ranks } \
\hline 13.1 & 1 & 100.9 & 7 \
\hline 16.9 & 2 & 111.2 & 8 \
\hline 24.2 & 3 & 113.5 & 9 \
\hline 30.6 & 4 & 151.1 & 10 \
\hline 32.8 & 5 & 172.3 & 11 \
\hline 41.1 & 6 & 206.6 & 12 \
\hline 218.8 & 13 & 442.4 & 14 \
\hline n _ { d } = 7 & T _ { d } = 34 & n _ { b } = 7 & T _ { b } = 71 \
\hline
\end{array}$

Quizplus · Accepted Answer

The Mann-Whitney statistic U is calculated as follows:$$U = n_1n_2 + \frac{n_1(n_1+1)}{2} - T_1$$where $n_1$ and $n_2$ are the sample sizes of the two groups, and $T_1$ is the sum of the ranks of the first group.In this case, $n_1 = 7$, $n_2 = 7$, and $T_1 = 34$. Therefore,$$U = 7 	imes 7 + \frac{7(7+1)}{2} - 34 = 49 + 28 - 34 = 43$$Therefore, the correct answer is A.

Given the Following Data,calculate the Mann-Whitney Statistic U for the Stream