Growth by any population with pulsed reproduction can be modeled as
A) $\frac { d N } { d t } = r _ { \max } N \left( \frac { K - N } { K } \right)$
B) $\frac { d N } { d t } = r _ { \max } N$
C) $N _ { t } = N _ { 0 } e ^ { r _ { \max } N }$
D) $N _ { t } = N _ { 0 } \lambda ^ { t }$
E) $\frac { d N } { d t } = r _ { \max } N \left( 1 - \frac { N } { K } \right)$

Question

Quizplus · Accepted Answer

Pulsed reproduction is best modeled by geometric growth, represented by $N _ { t } = N _ { 0 } \lambda ^ { t }$, where $\lambda$ is the finite rate of increase.

Growth by Any Population with Pulsed Reproduction Can Be Modeled dNdt=rmax⁡N(K−NK)\frac { d N } { d t } = r _ { \max } N \left( \frac { K - N } { K } \right)dtdN​=rmax​N(KK−N​)

Growth by Any Population with Pulsed Reproduction Can Be Modeled $\frac { d N } { d t } = r _ { \max } N \left( \frac { K - N } { K } \right)$