The cross GE/ge × ge/ge produces the following progeny: GE/ge 404; ge/ge 396; gE/ge 97; Ge/ge 103.From these data one can conclude that there are 20 map units between the G and E loci.

Question

Quizplus · Accepted Answer

The fact that there are 404 GE/ge, 396 ge/ge, 97 gE/ge, and 103 Ge/ge progeny from the cross indicates that the G and E loci are closely linked, with some degree of interference. By summing the frequencies of the recombinant classes (gE/ge and Ge/ge), the total number of recombinants is found to be 200, which equals 1/5th of the total progeny (1000). Thus, the distance between the G and E loci is 20 map units (or centimorgans), which is the percentage of recombinant progeny. Therefore, the statement is true.

The Cross GE/ge × Ge/ge Produces the Following Progeny: GE/ge