What mass of sodium hydroxide is necessary to react with a solution containing 73.00 g HCl,according to the chemical equation below? [Molar masses: NaOH,39.99 g/mol; HCl,36.45 g/mol] NaOH(aq)+ HCl(aq)→ NaCl(aq)+ H₂O(l)

Question

Quizplus · Accepted Answer

The balanced chemical equation is:NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l)From the equation, we can see that 1 mole of NaOH reacts with 1 mole of HCl.The molar mass of NaOH is 39.99 g/mol, and the molar mass of HCl is 36.45 g/mol.Therefore, the mass of NaOH required to react with 73.00 g of HCl is:mass of NaOH = (73.00 g HCl) × (1 mol HCl / 36.45 g HCl) × (1 mol NaOH / 1 mol HCl) × (39.99 g NaOH / 1 mol NaOH)= 80.09 g NaOHTherefore, the correct answer is A.

What Mass of Sodium Hydroxide Is Necessary to React with a Solution