The pK_a of acetic acid, CH₃COOH, is 4.76. What is the value of the equilibrium constant K_eq, for the following equilibrium? [The concentration of water in a dilute aqueous solution is 55 M] $\mathrm{CH}_{3} \mathrm{COOH}+\mathrm{H}_{2} \mathrm{O}=\mathrm{H}_{3} \mathrm{O}^{\oplus}+\mathrm{CH}_{3} \mathrm{COO}^{\ominus}$ A) 3.2 × 10⁷ B) ?3.2 × 10?⁷ C) ?3.2 × 10⁷ D) 3.2 × 10?⁷

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The Answer of The pK_a of acetic acid, CH₃COOH, is 4.76. What is the value of the equilibrium constant K_eq, for the following equilibrium? [The concentration of water in a dilute aqueous solution is 55 M] $\mathrm{CH}_{3} \mathrm{COOH}+\mathrm{H}_{2} \mathrm{O}=\mathrm{H}_{3} \mathrm{O}^{\oplus}+\mathrm{CH}_{3} \mathrm{COO}^{\ominus}$ A) 3.2 × 10⁷ B) ?3.2 × 10?⁷ C) ?3.2 × 10⁷ D) 3.2 × 10?⁷

The PKa of Acetic Acid, CH3COOH, Is 4 CH3COOH+H2O=H3O⊕+CH3COO⊖\mathrm{CH}_{3} \mathrm{COOH}+\mathrm{H}_{2} \mathrm{O}=\mathrm{H}_{3} \mathrm{O}^{\oplus}+\mathrm{CH}_{3} \mathrm{COO}^{\ominus}CH3​COOH+H2​O=H3​O⊕+CH3​COO⊖

The PK_a of Acetic Acid, CH₃COOH, Is 4 $\mathrm{CH}_{3} \mathrm{COOH}+\mathrm{H}_{2} \mathrm{O}=\mathrm{H}_{3} \mathrm{O}^{\oplus}+\mathrm{CH}_{3} \mathrm{COO}^{\ominus}$