Why does a Shapiro-Wilk test sometimes conclude that the data are not normally distributed (i.e. significant) when a Kolmogorov-Smirnov test is non-significant?
A) The Shapiro-Wilk test is more powerful.
B) The Shapiro-Wilk test is less powerful.
C) The Shapiro-Wilk test does not work well when there are a large number of cases.
D) The Shapiro-Wilk test is a more conservative test.
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