The ionization energy of the hydrogen atom is 13.6 eV.What is the energy of a photon emitted corresponding to a transition from the n = 6 to n = 2 state?
A) 7.9 eV
B) 2.9 eV
C) 3.0 eV
D) 4.0 eV

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The Answer of The ionization energy of the hydrogen atom is 13.6 eV.What is the energy of a photon emitted corresponding to a transition from the n = 6 to n = 2 state?
A) 7.9 eV
B) 2.9 eV
C) 3.0 eV
D) 4.0 eV

The Ionization Energy of the Hydrogen Atom Is 13